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A Hard Day's Night solution in Clear category for Friendly Number by dorellaurent
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
"""
Format a number as friendly text, using common suffixes.
"""
from math import trunc
pow = 0
pe = trunc(number/(base**pow))
while abs(pe) >= base and pow < len(powers) - 1 :
pow += 1
pe = trunc(number/(base**pow))
if decimals == 0 :
return ''.join([str(pe), powers[pow], suffix])
else :
nb = round(number/(base**pow), decimals)
s_nb= ''.join(['%.',str(decimals),'f']) % nb
return ''.join([s_nb, powers[pow], suffix])
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
Jan. 26, 2018
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