nested lambda clear solution for Frequency Sorting by zshlab - python coding challenges

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nested lambda solution in Clear category for Frequency Sorting by zshlab

frequency_sorting = lambda numbers: sorted(numbers, key=lambda x: (-numbers.count(x), x))


print("Example:")
print(list(frequency_sorting([1, 2, 3, 4, 5])))

# These "asserts" are used for self-checking
assert list(frequency_sorting([1, 2, 3, 4, 5])) == [1, 2, 3, 4, 5]
assert list(frequency_sorting([3, 4, 11, 13, 11, 4, 4, 7, 3])) == [
    4,
    4,
    4,
    3,
    3,
    11,
    11,
    7,
    13,
]

print("The mission is done! Click 'Check Solution' to earn rewards!")

Feb. 16, 2025

Comments:

sanddro on Feb. 23, 2025, 8:24 p.m.
<p>Great. I like the way of using several conditions for the builtin sorting function:</p> <pre class='brush: python'>key=lambda x: (-numbers.count(x), x) </pre>

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