Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Frequency Sorting by mikehult123
from collections.abc import Iterable
def frequency_sorting(numbers: list[int]) -> Iterable[int]:
# replace this for solution
return sorted(sorted(numbers), key=numbers.count, reverse=True)
print("Example:")
print(list(frequency_sorting([1, 2, 3, 4, 5])))
# These "asserts" are used for self-checking
assert list(frequency_sorting([1, 2, 3, 4, 5])) == [1, 2, 3, 4, 5]
assert list(frequency_sorting([3, 4, 11, 13, 11, 4, 4, 7, 3])) == [
4,
4,
4,
3,
3,
11,
11,
7,
13,
]
print("The mission is done! Click 'Check Solution' to earn rewards!")
May 12, 2023
