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Just simple flatten solution in Clear category for The Flat Dictionary by obone
def flatten(dictionary):
a = {}
for k, v in dictionary.items():
if v == {}:
a.setdefault(k, "")
elif type(v) == type({}):
a.update({k + '/' + kk : vv for kk, vv in flatten(v).items()})
else:
a.setdefault(k, v)
return a
June 16, 2019
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