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The Flat Dictionary solution in Uncategorized category for The Flat Dictionary by Agnieszka_Dziudzi
def flatten(dictionary: dict[str, str | dict]) -> dict[str, str]:
# your code here
def recurse(subdict, prefix):
if not subdict:
flattened_dict[prefix] = ""
return
for k, v in subdict.items():
new_key = f"{prefix}/{k}" if prefix else k
if isinstance(v, dict):
recurse(v, new_key)
else:
flattened_dict[new_key] = v
flattened_dict = {}
recurse(dictionary, "")
return flattened_dict
print("Example:")
print(flatten({"key": "value"}))
# These "asserts" are used for self-checking
assert flatten({"key": "value"}) == {"key": "value"}
assert flatten({"key": {"deeper": {"more": {"enough": "value"}}}}) == {
"key/deeper/more/enough": "value"
}
assert flatten({"empty": {}}) == {"empty": ""}
assert flatten(
{
"name": {"first": "One", "last": "Drone"},
"job": "scout",
"recent": {},
"additional": {"place": {"zone": "1", "cell": "2"}},
}
) == {
"name/first": "One",
"name/last": "Drone",
"job": "scout",
"recent": "",
"additional/place/zone": "1",
"additional/place/cell": "2",
}
print("The mission is done! Click 'Check Solution' to earn rewards!")
May 27, 2024
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