Fizz Buzz clear solution for Fizz Buzz by typhonic - python coding challenges

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Fizz Buzz solution in Clear category for Fizz Buzz by typhonic

def checkio(number):
    if not number % 15:
        return('Fizz Buzz')
    elif not number % 5:
        return('Buzz')
    elif not number % 3:
        return('Fizz')
    else:
        return(str(number))
    

#Some hints:
#Convert a number in the string with str(n)

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
    assert checkio(6) == "Fizz", "6 is divisible by 3"
    assert checkio(5) == "Buzz", "5 is divisible by 5"
    assert checkio(7) == "7", "7 is not divisible by 3 or 5"

Oct. 16, 2016

Comments:

glenuk on Oct. 17, 2016, 10:38 p.m.
I never thought of using 15 to do a single division.

DahliaSR on Nov. 4, 2016, 8:45 p.m.
I like the idea of using of using not instead of == 0, might be a bit more challenging to get how it works but once you got it you learned that you can interprete integers as booleans. I don't like the redundant parentheses in your return statements, they are useless. The elif-statements are useless, too. When the if-statement before evaluates to True the elif-statement will never be reached, coz you already use return in the if-statement.

typhonic on Nov. 7, 2016, 4:35 a.m.
DahliaSR Thanks for the review. You are right about the useless redundancy of using elif after a return and about the extra parentheses. I did not realize I was doing the first, and I only just recently learned not to use parentheses in the return. ...John

DahliaSR on Nov. 7, 2016, 6:54 p.m.
Any time :D

Strings and Integers

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