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First solution in Clear category for Fizz Buzz by muhammed56
def checkio(num: int) -> str:
if num % 3 == 0 and num % 5 == 0:
return "Fizz Buzz"
elif num % 3 == 0:
return "Fizz"
elif num % 5 == 0:
return "Buzz"
else:
return str(num)
Oct. 20, 2025