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divmod solution in Speedy category for Fizz Buzz by gtff
def checkio(number: int) -> str:
div_by_three = not(divmod(number, 3)[1])
if divmod(number, 5)[1]:
## not divisible by 5
if div_by_three:
return "Fizz"
else:
## divisible by 5
if div_by_three:
return "Fizz Buzz"
return "Buzz"
return str(number)
if __name__ == '__main__':
print('Example:')
print(checkio(15))
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Oct. 27, 2020
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