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Second solution in Creative category for Fizz Buzz by H4stoor
def checkio(number):
answer = (('', 'Fizz ')[number % 3 == 0] + ('', 'Buzz ')[number % 5 == 0]).strip()
return answer if answer else str(number)
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Dec. 27, 2016
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