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Fizz Buzz solution in Clear category for Fizz Buzz by EfGnevsheva
def checkio(a):
if a%3==0 and a%5==0 :
return 'Fizz Buzz'
elif a%3==0 :
return 'Fizz'
elif a%5==0:
return 'Buzz'
else :
return str(a)
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Sept. 18, 2015
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