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First solution in Uncategorized category for Fizz Buzz by ArkadiuszFrankowiak
def checkio(liczba):
if liczba % 15 == 0:
return ('Fizz Buzz')
if liczba % 5 ==0:
return('Buzz')
if liczba%3==0:
return('Fizz')
else:
return str(liczba)
Nov. 15, 2015
