Second clear solution for Fizz Buzz by ArchTauruS - python coding challenges - Py.CheckiO

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Second solution in Clear category for Fizz Buzz by ArchTauruS

def checkio(number):
    return ' '.join(('Fizz' * (number%3 == 0), 'Buzz' * (number%5 == 0))).strip() or str(number)

Oct. 28, 2018

Strings and Integers

0

0 %

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