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First solution in Clear category for Fizz Buzz by Alex-Elf
def checkio(number: int) -> str:
if number % 15 == 0:
return "Fizz Buzz"
elif number % 3 == 0:
return 'Fizz'
elif number % 5 == 0:
return 'Buzz'
else:
return str(number)
Nov. 20, 2018
