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First solution in Uncategorized category for Fizz Buzz by Albert.Nowak
def czy_przez_trzy(number):
suma = 0
dl = len(number)
for eachNumber in number:
suma = suma + int(eachNumber)
if suma%3 == 0:
return 1
else:
return 0
def czy_przez_piec(number):
dl=len(number)
ost = number[dl-1]
x = int(ost)
if x==5 or x==0:
return 1
else:
return 0
def checkio(number):
liczba = str(number)
wynik1=czy_przez_piec(liczba)
wynik2=czy_przez_trzy(liczba)
if wynik1==1 and wynik2==1:
return "Fizz Buzz"
elif wynik1==1:
return "Buzz"
elif wynik2==1:
return "Fizz"
elif wynik1==0 or wynik2==0:
return liczba
#Some hints:
#Convert a number in the string with str(n)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Dec. 14, 2015
