First Word clear solution for First Word by W.Zalicki - python coding challenges

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First Word solution in Clear category for First Word by W.Zalicki

def first_word(text: str) -> str:
    import re
    text = text.strip('.')
    text = text.strip()
    word = re.split('[, .]',text)
    return word[0]

Jan. 14, 2018

Comments:

JanisVigulis on Jan. 21, 2018, 11:31 a.m.
First of all I am noob at programming. It seems that this code does not work for this kind of text: <pre class='brush: python'>print(first_word(" .,code's,. ,day, a, d.j go")) </pre> I tested and I found out that characters '.,' before 'code's' is messing it up. Or am I missing something in the missions description?

Jon_Red on March 30, 2020, 9:01 p.m.
Well I'm a noob at checkio but not a noob at programming and I believe you are correct, sir. It's weird that this solution didn't fail the test and also got so many upvotes.

olevoniuk on Dec. 16, 2020, 8:02 a.m.
I do not understand the reason, you used strip function here. All you need is to find sequence of letters, so would be totally enough using something like re.serach(pattern, text).

Adrian_Goh on Jan. 7, 2021, 5:39 p.m.
might be easier to do a search than to strip. Here's what I tried. <pre class='brush: python'>p = re.compile(r'\w+\'?\w*') return p.search(text).group() </pre>

rodrumt on Oct. 18, 2021, 3:43 p.m.
A lot of lines of code. One return line would be enough for simple challenges

hbczmxy on Feb. 19, 2022, 3:21 a.m.
as JanisVigulis said, if the argument text is " .,code's,. ,day, a, d.j go", your function will return an empty string. The reason for this is that the first 3 elements of the list returned by re.split are empty strings. If the argument text is " .,code's,. ,day, a, d.j go", the result of re.split in your function will be： <pre class='brush: python'>['', '', '', "code's", '', '', '', 'day', '', 'a', '', 'd', 'j', 'go'] </pre> So if you still use re.split, you should pick out non-empty strings My suggestion is only use re.split, as follows: <pre class='brush: python'>import re def first_word(text: str) -> str: return [word for word in re.split('[, .]',text) if word != ''][0] </pre>

k.doguzov on Dec. 29, 2022, 1:38 p.m.
Just one more way. <pre class='brush: python'>import re def first_word(text: str) -> str: text = re.split(r'[^a-zA-Z\']', text.strip(",. ")) return text[0] </pre>

Strings and Integers

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