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First solution in Clear category for Find Sequence by marcelina.gorzelana
def checkio(matrix):
res = False
for i in range(len(matrix)):
for j in range (len(matrix)):
if i < len(matrix) - 3 and j < len(matrix) - 3:
k = 1
while k < 4 and matrix[i+k][j+k] == matrix[i][j]:
k += 1
if k == 4:
res = True
break
if i < len(matrix) - 3 and j >= len(matrix) - 3:
k = 1
while k < 4 and matrix[i+k][j-k] == matrix[i][j]:
k += 1
if k == 4:
res = True
break
if i < len(matrix) - 3:
k = 1
while k< 4 and matrix[i+k][j] == matrix[i][j]:
k += 1
if k == 4:
res = True
break
if j < len(matrix) - 3:
k = 1
while k < 4 and matrix[i][j+k] == matrix[i][j]:
k += 1
if k == 4:
res = True
break
return res
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
[1, 2, 1, 1],
[1, 1, 4, 1],
[1, 3, 1, 6],
[1, 7, 2, 5]
]) == True, "Vertical"
assert checkio([
[7, 1, 4, 1],
[1, 2, 5, 2],
[3, 4, 1, 3],
[1, 1, 8, 1]
]) == False, "Nothing here"
assert checkio([
[2, 1, 1, 6, 1],
[1, 3, 2, 1, 1],
[4, 1, 1, 3, 1],
[5, 5, 5, 5, 5],
[1, 1, 3, 1, 1]
]) == True, "Long Horizontal"
assert checkio([
[7, 1, 1, 8, 1, 1],
[1, 1, 7, 3, 1, 5],
[2, 3, 1, 2, 5, 1],
[1, 1, 1, 5, 1, 4],
[4, 6, 5, 1, 3, 1],
[1, 1, 9, 1, 2, 1]
]) == True, "Diagonal"
Nov. 21, 2016
