First clear solution for Feed Pigeons by radekj - python coding challenges

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First solution in Clear category for Feed Pigeons by radekj

from collections import defaultdict

def checkio(food):
    minute = pigeons = 0
    fed_pigeons = defaultdict(int)

    while food:
        minute += 1
        pigeons += minute

        # feed pigeons
        for pigeon in range(pigeons):
            if food:
                food -= 1
                fed_pigeons[pigeon] += 1

    return len(fed_pigeons)

April 8, 2015

Comments:

mlb00 on July 22, 2015, 9:06 p.m.
clever solution!

robert.bedner on March 14, 2022, 11:17 a.m.
Nice solution! I'm undecided, if I like the pythonic style of "while food" and "if food"... it is short and readable, but it doesn't tell a story. You could name the variable food_remaining: <pre class='brush: python'>from collections import defaultdict def checkio(food): minute = pigeons = 0 fed_pigeons = defaultdict(int) food_remaining = food while food_remaining: minute += 1 pigeons += minute for pigeon in range(pigeons): if not food_remaining: break food_remaining -= 1 fed_pigeons[pigeon] += 1 return len(fed_pigeons) </pre> You could invert the if-statement like shown.

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