Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First (='ω'=) solution in Clear category for Feed Pigeons by Magu
from itertools import count
def checkio(number):
lst = [1]
for s in count(1):
for _ in range(s + 1): lst.append(0)
for t in range(len(lst)):
if sum(lst) == number: break # break inner loop
lst[t] += 1
else: continue # without inner loop break
break # break outer loop
return len([n for n in lst if n])
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
#assert checkio(3) == 2
assert checkio(1) == 1, "1st example"
assert checkio(2) == 1, "2nd example"
assert checkio(5) == 3, "3rd example"
assert checkio(10) == 6, "4th example"
Oct. 20, 2021
Comments:
