First clear solution for The End of Other by l.szyman10 - python coding challenges

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First solution in Clear category for The End of Other by l.szyman10

def checkio(words_set):
    words_set = list(words_set)
    words_set.sort(key = len, reverse = True)

    while(words_set):
        check = words_set.pop()    
        for word in words_set:
            if len(check) < len(word) and check == word[-len(check):]:
                return True
    return False

Aug. 12, 2020

Comments:

pandektis on Feb. 13, 2021, 9:15 p.m.
<p>Well I had the same idea, sorting and emptying the set, to minimize loop rounds. I like this for not creating an extra list (I used sorted()) and the while , pop() are more clear. Why not use str.endswith() in the conditional?</p>

l.szyman10 on Feb. 16, 2021, 12:27 p.m.
<p>Just didn't think about using str.endswith(), you're right - it'd be better solution. Thanks for review :)</p>

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