Second clear solution for Digits Multiplication by tokiojapan55 - python coding challenges

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Second solution in Clear category for Digits Multiplication by tokiojapan55

from functools import reduce
def checkio(number: int) -> int:
    return reduce(lambda a, b: int(b) * a, str(number).replace('0', ''), 1)

Dec. 26, 2023

Comments:

zshlab on Feb. 1, 2025, 10:34 p.m.
nice and clear! what is the 1 at the end for?

tokiojapan55 on Feb. 3, 2025, 3:16 a.m.
The third argument of produce() is initializer. My understanding is as follows. For example, if produce() is called with the array [5, 4, 3, 2, 1], without initializer, the first call will start with 5 * 4, using the first and second array elements. If initializer is set to 6, the first call will start at 6 * 5, using the initializer and the top of the array. In this solution, if the lambda is 'int(b) * int(a)', the initializer is not necessary, but since int(a) is redundant after the second call, the initializer is set to 'int(b) * a' by setting it to 1.

zshlab on Feb. 9, 2025, 4:42 p.m.
Thank you very much!

Strings and Integers

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