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Should be self-explanatory solution in Clear category for Date and Time Converter by Selindian
def date_time(time: str) -> str:
# replace this for solution
trl_month = {1: "January", 2: "February", 3: "March", 4: "April",
5: "May", 6: "June", 7: "July", 8: "August",
9:"September", 10:"October", 11:"November", 12: "December"}
date, time = time.split(' ') # As we could have years < 1000 split into date + time
day = int(date[0:2])
month = trl_month[int(date[3:5])]
year = int(date[6:])
hour = int(time[0:2])
minute = int(time[3:])
str_minute = ("minute" if minute == 1 else "minutes")
str_hour = ("hour" if hour == 1 else "hours")
time = "{} {} {} year {} {} {} {}".format(day, month, year, hour, str_hour, minute, str_minute)
return time
if __name__ == "__main__":
print("Example:")
print(date_time("01.01.2000 00:00"))
# These "asserts" using only for self-checking and not necessary for auto-testing
assert (
date_time("01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes"
), "Millenium"
assert (
date_time("09.05.1945 06:30") == "9 May 1945 year 6 hours 30 minutes"
), "Victory"
assert (
date_time("20.11.1990 03:55") == "20 November 1990 year 3 hours 55 minutes"
), "Somebody was born"
print("Coding complete? Click 'Check' to earn cool rewards!")
March 4, 2022
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