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First solution in Clear category for Moore Neighbourhood by lukasz.bogaczynski
def count_neighbours(board, row, column):
neighbours_count = 0
for i in range(-1, 2):
for j in range(-1, 2):
if row + i == row and column + j == column:
continue
if row + i > len(board) - 1 or row + i < 0 or column + j > len(board[0]) - 1 or column + j < 0:
continue
if board[row + i][column + j] == 1:
neighbours_count += 1
return neighbours_count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
Nov. 27, 2017
