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First solution in Clear category for Count Inversions by Gabor_thepolip
def count_inversion(seq):
count = 0
for idx, val in enumerate(seq):
index = idx + 1
while index <= len(seq)-1:
if val > seq[index]:
count += 1
index += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_inversion((1, 2, 5, 3, 4, 7, 6)) == 3, "Example"
assert count_inversion((0, 1, 2, 3)) == 0, "Sorted"
assert count_inversion((99, -99)) == 1, "Two numbers"
assert count_inversion((5, 3, 2, 1, 0)) == 10, "Reversed"
Nov. 22, 2017
