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First solution in Clear category for Compare Functions by mu_py
def checkio(f,g):
""" returns a function that combines functions f & g. The latter used as a backup """
def h(*args,**kwargs):
# check the results of f() and g()
try: f_res = f(*args,**kwargs)
except: f_res = None
try: g_res = g(*args,**kwargs)
except: g_res = None
# both functions have a result <> None: return result of f()
if f_res!=None and g_res!=None:
return (f_res, 'same') if f_res == g_res else (f_res,'different')
# both functions fail: return None
if f_res == g_res == None:
return None,'both_error'
# only one function has a result <> None: return that result
return (f_res, 'g_error') if f_res != None else (g_res,'f_error')
return h
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
# (x+y)(x-y)/(x-y)
assert checkio(lambda x,y:x+y,
lambda x,y:(x**2-y**2)/(x-y))\
(1,3)==(4,'same'), "Function: x+y, first"
assert checkio(lambda x,y:x+y,
lambda x,y:(x**2-y**2)/(x-y))\
(1,2)==(3,'same'), "Function: x+y, second"
assert checkio(lambda x,y:x+y,
lambda x,y:(x**2-y**2)/(x-y))\
(1,1.01)==(2.01,'different'), "x+y, third"
assert checkio(lambda x,y:x+y,
lambda x,y:(x**2-y**2)/(x-y))\
(1,1)==(2,'g_error'), "x+y, fourth"
# Remove odds from list
f = lambda nums:[x for x in nums if ~x%2]
def g(nums):
for i in range(len(nums)):
if nums[i]%2==1:
nums.pop(i)
return nums
assert checkio(f,g)([2,4,6,8]) == ([2,4,6,8],'same'), "evens, first"
assert checkio(f,g)([2,3,4,6,8]) == ([2,4,6,8],'g_error'), "evens, second"
# Fizz Buzz
assert checkio(lambda n:("Fizz "*(1-n%3) + "Buzz "*(1-n%5))[:-1] or str(n),
lambda n:('Fizz'*(n%3==0) + ' ' + 'Buzz'*(n%5==0)).strip())\
(6)==('Fizz','same'), "fizz buzz, first"
assert checkio(lambda n:("Fizz "*(1-n%3) + "Buzz "*(1-n%5))[:-1] or str(n),
lambda n:('Fizz'*(n%3==0) + ' ' + 'Buzz'*(n%5==0)).strip())\
(30)==('Fizz Buzz','same'), "fizz buzz, second"
assert checkio(lambda n:("Fizz "*(1-n%3) + "Buzz "*(1-n%5))[:-1] or str(n),
lambda n:('Fizz'*(n%3==0) + ' ' + 'Buzz'*(n%5==0)).strip())\
(7)==('7','different'), "fizz buzz, third"
Jan. 8, 2023
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