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First solution in Clear category for Common Words by szymonkukla1
def checkio(first, second):
common = ''
y = []
z = []
k = []
y = first.split(",")
z = second.split(",")
i = 0
while(i < len(y)):
m = 0
while(m < len(z)):
if(y[i]==z[m]):
k.append(y[i])
m = m + 1
i = i + 1
w = ",".join(sorted(k))
return(w)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("hello,world", "hello,earth") == "hello", "Hello"
assert checkio("one,two,three", "four,five,six") == "", "Too different"
assert checkio("one,two,three", "four,five,one,two,six,three") == "one,three,two", "1 2 3"
Nov. 14, 2016