First clear solution for Common Words by sebsch - python coding challenges

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First solution in Clear category for Common Words by sebsch

def checkio(first, second):
    return ",".join(sorted([w for w in first.split(',') if w in second.split(',')]))

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio("hello,world", "hello,earth") == "hello", "Hello"
    assert checkio("one,two,three", "four,five,six") == "", "Too different"
    assert checkio("one,two,three", "four,five,one,two,six,three") == "one,three,two", "1 2 3"

April 30, 2016

Comments:

Flying_Eye on May 23, 2016, 9:27 a.m.
<p>`second.split(',')` statement is envoked `len(first.split(','))` times. It is better to assign it to some variable first:</p> <pre class='brush: python'>sec = set(second.split(',')) return ",".join(sorted([w for w in first.split(',') if w in sec])) </pre>

Strings Theory

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