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First solution in Clear category for Common Words by iwo.malyszka
# migrated from python 2.7
def checkio(first, second):
first = str(first)
second = str(second)
new_first = []
new_second = []
for word in first.split(','):
new_first.append(word)
for word in second.split(','):
new_second.append(word)
words = []
in_second = False
a = []
for i in new_first:
if i in new_second:
in_second = True
words.append(i)
if in_second:
a = ','.join(sorted(words))
return str(a)
else:
return ""
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("hello,world", "hello,earth") == "hello", "Hello"
assert checkio("one,two,three", "four,five,six") == "", "Too different"
assert checkio("one,two,three", "four,five,one,two,six,three") == "one,three,two", "1 2 3"
Oct. 29, 2016
