First clear solution for CheckSum by Tinus_Trotyl - python coding challenges

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First solution in Clear category for CheckSum by Tinus_Trotyl

def checkio(data):
    digits = [ord(c) - 48 for c in data[::-1] if '0' <= c <= '9' or 'A' <= c <= 'Z']
    cumulo = sum(n if i&1 else sum(divmod(2 * n, 10)) for i, n in enumerate(digits))
    return [str((10 - (cumulo % 10)) % 10), cumulo]

June 15, 2019

Comments:

lisovsky on Jan. 27, 2023, 11:52 a.m.
i&1 instead of not i%2 ?

Tinus_Trotyl on Jan. 28, 2023, 3:46 a.m.
`i&1` gives the same result as `not i%2` but for me `i&1` is a more direct way in this case. I admit that `i&1` may be a "lower level" expression, but at least it's shorter and requires fewer operations.

Hermit

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