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chr,ord - ASCII solution in Clear category for Caesar Cipher (encryptor) by vlader
def to_encrypt(text, delta):
#replace this for solution
encrypt = ''
for l in text:
if l == ' ':
encrypt += ' '
else:
i = ord(l) - ord('a')
i += delta
i %= 26
i += ord('a')
encrypt += chr(i)
return encrypt
if __name__ == '__main__':
print("Example:")
print(to_encrypt('abc', 10))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert to_encrypt("a b c", 3) == "d e f"
assert to_encrypt("a b c", -3) == "x y z"
assert to_encrypt("simple text", 16) == "iycfbu junj"
assert to_encrypt("important text", 10) == "swzybdkxd dohd"
assert to_encrypt("state secret", -13) == "fgngr frperg"
print("Coding complete? Click 'Check' to earn cool rewards!")
July 24, 2018
