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Closure solution in Creative category for Building Visibility by veky
def checkio(b):
def v(d,r=False,z={}):
for x in range(d[0],d[2]):
if d[4]>z.get(x,0): r,z[x]=True,d[4]
return r
return sum(map(v,sorted(b,key=lambda d: d[1])))
June 23, 2013
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