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First solution in Uncategorized category for Brackets by capback250
# migrated from python 2.7
def checkio(text):
sk = list(i for i in text if i in list('({['))
a = []
i = 0
for let in text:
if let in "({[":
a.append(let)
elif let in ")}]":
if a:
temp = a.pop()
if temp == "(" and let == ")" or\
temp == "{" and let == "}" or\
temp == "[" and let == "]":
i += 1
else:
return False
if len(sk) == i:
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 30, 2015
