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First solution in Uncategorized category for Brackets by Rounin
import re
def checkio(expression):
expression = list(re.sub('[^()\[\]{}]', '', expression))
opens = {'(':')', '[':']', '{':'}'}
queue=[]
while len(expression) > 0:
if expression[0] in opens:
queue.append(expression[0])
elif (len(queue) < 1) or (opens[queue.pop()] != expression[0]):
return False
expression = expression[1:]
return (len(queue) == 0)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 23, 2017