Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Brackets by Poetakodu
def checkio(exp):
nawiasy = "()[]{}"
string = ""
for abc in exp:
if abc in nawiasy:
string += abc
if len(string) % 2 != 0:
return False
while string.find("()") != -1 or string.find("{}") != -1 or string.find("[]") != -1:
string = string.replace("()","")
string = string.replace("{}","")
string = string.replace("[]","")
if string != "":
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Nov. 4, 2016
