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stack solution in Clear category for Brackets by Minnozz
BRACKETS = {
"(": ")",
"{": "}",
"[": "]",
}
def checkio(expression):
expect = []
for char in expression:
if char not in "(){}[]":
continue
if char in BRACKETS: #Open
expect.append(BRACKETS[char])
else: #Close
if not expect: #Extra close bracket
return False
if char != expect.pop(): #Different close bracket
return False
if expect: #Missing close bracket
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 17, 2014
