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First solution in Uncategorized category for Brackets by Mahoter
def checkio(expression):
brackets = []
for letter in expression:
if letter == '(' or letter == ')' or letter == '[' or letter == ']' or letter == '{' or letter == '}' :
brackets += [letter]
while len(brackets) > 0:
temp = len(brackets)
a = 0
while a < len(brackets)-1:
if brackets[a] == '(' and brackets[a+1] == ')' or brackets[a] == '[' and brackets[a+1] == ']' or brackets[a] == '{' and brackets[a+1] == '}':
x = brackets.pop(a+1)
x = brackets.pop(a)
print(len(brackets))
a +=1
if temp == len(brackets):
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Jan. 17, 2016
