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First solution in Clear category for Binary Count by Rafal.U
def checkio(number):
lista = []
counter = 0
while number != 0:
reszta = number%2
if reszta == 1: counter += 1 # ilosc wystapienia "1" w postaci binarnej liczby
number -= reszta
number /= 2
lista.append(reszta)
lista.reverse() # liczba dziesietna z wejscia w postaci binarnej
return counter
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(4) == 1
assert checkio(15) == 4
assert checkio(1) == 1
assert checkio(1022) == 9
Nov. 8, 2016
