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First solution in Clear category for Bigger Price by anieruth
def bigger_price(limit, data):
# Sort the list by price (descending) and take the first 'limit' items
return sorted(data, key=lambda x: x["price"], reverse=True)[:limit]
print("Example:")
print(
bigger_price(
2,
[
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1},
],
)
)
assert bigger_price(
2,
[
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1},
],
) == [{"name": "wine", "price": 138}, {"name": "bread", "price": 100}]
assert bigger_price(
1, [{"name": "pen", "price": 5}, {"name": "whiteboard", "price": 170}]
) == [{"name": "whiteboard", "price": 170}]
print("The mission is done! Click 'Check Solution' to earn rewards!")
Oct. 20, 2025
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