1-liner: shorty clear solution for Ascending List by przemyslaw.daniel - python coding challenges

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1-liner: shorty solution in Clear category for Ascending List by przemyslaw.daniel

is_ascending = lambda x: sorted(set(x)) == x

Nov. 1, 2018

Comments:

BrianMcleod on Nov. 2, 2018, 2 p.m.
Nice!!! Perfect solution.

BrianMcleod on Nov. 2, 2018, 2:02 p.m.
Nice and concise!

ProgrammerBruce on April 11, 2020, 3 p.m.
Short and clear, but O(n log n) to sort instead of O(n) for just a little more code.

Darkalkemy on Aug. 25, 2020, 12:12 p.m.
Why use Lambda function at all? <pre class='brush: python'>return x == sorted(set(x)) </pre> should work fine as well. Or am I missing something?

przemyslaw.daniel on Aug. 25, 2020, 3:52 p.m.
<pre class='brush: python'>def is_ascending(x): return x == sorted(set(x)) </pre> to have shorter code

graou on Jan. 27, 2021, 12:22 a.m.
not quick, but smart

List but not the least

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