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First solution in Clear category for Armstrong Number Checking by kavishhh
def is_armstrong(num: int) -> bool:
# your code here
digits = [int(d) for d in str(num)]
power = len(digits)
total = sum(d ** power for d in digits)
return total == num
print("Example:")
print(is_armstrong(11))
# These "asserts" are used for self-checking
assert is_armstrong(153) == True
assert is_armstrong(370) == True
assert is_armstrong(947) == False
assert is_armstrong(371) == True
assert is_armstrong(407) == True
assert is_armstrong(163) == False
assert is_armstrong(100) == False
assert is_armstrong(8208) == True
assert is_armstrong(930) == False
assert is_armstrong(4) == True
print("The mission is done! Click 'Check Solution' to earn rewards!")
Oct. 20, 2025
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