splice and check clear solution for All the Same by imtiaz.rahi - python coding challenges

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splice and check solution in Clear category for All the Same by imtiaz.rahi

def all_the_same(elements) -> bool:
    return elements[1:] == elements[:-1]

Oct. 30, 2019

Comments:

phillipnwts on Nov. 22, 2019, 11:44 p.m.
This is clean and concise. To the new programmers it might be a little vague on how it works.

imtiaz.rahi on Nov. 23, 2019, 1:54 p.m.
agreed. So, I am attaching explanation given by in comments of another solution. <blockquote> elements[1:] makes a copy of the list without the first item, as list index starts with 0. elements[:-1] makes a copy of the list without the last item, as item with index -1 (the last) is not included. When these two copies are compared, the first item is compared to the second, the second to the third, and so on. As a result, every item is compared to the next. If all comparisons give True, all items are equal. </blockquote> <a href="https://py.checkio.org/mission/all-the-same/publications/tom-tom/python-3/fifth/share/7a1e3e04b987e309fea0b60a3ba9b6b2/">https://py.checkio.org/mission/all-the-same/publications/tom-tom/python-3/fifth/share/7a1e3e04b987e309fea0b60a3ba9b6b2/</a>#comment-71947

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