len if isdigit clear solution for Acceptable Password VI by m.kurapov - python coding challenges

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len if isdigit solution in Clear category for Acceptable Password VI by m.kurapov

def is_acceptable_password(password: str) -> bool:
    return password.lower().find('password')==-1 \
       and (len(password)>9
            or 
            len(password)>6 and \
            len(password)>len([x for x in password if x.isdigit()])>0
           ) \
       and len(set(password))>2

Nov. 18, 2020

Strings Theory

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