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First solution in Clear category for Acceptable Password IV by kxy_2333
def is_acceptable_password(word):
if len(word) >= 9:
return True
else:
return True if len(word)>6 and any([i.isdigit() for i in word]) and any([not i.isdigit() for i in word]) else False
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
print("Coding complete? Click 'Check' to earn cool rewards!")
May 4, 2022
