Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Use all & any in this one. solution in Speedy category for Acceptable Password III by rockwellshabani
# Taken from mission Acceptable Password II
def is_acceptable_password(password: str) -> bool:
"""Returns if password meets all requirements."""
num_test = [str.isnumeric(i) for i in password]
if all(num_test):
return False
else:
return (len(password) > 6 and
any(num_test))
if __name__ == '__main__':
print("Example:")
#print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('muchlonger5'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Aug. 1, 2020
Comments:
