Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Simple solution in Clear category for Acceptable Password III by mindaugas.dadurkevicius
def is_acceptable_password(password):
len_test = len(password) > 6
digit_test1 = max([ch.isdigit() for ch in password])
digit_test2 = not password.isdigit()
return len_test & digit_test1 & digit_test2
June 18, 2021
Comments: