Simple clear solution for Acceptable Password III by mindaugas.dadurkevicius - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

Simple solution in Clear category for Acceptable Password III by mindaugas.dadurkevicius

def is_acceptable_password(password):
    len_test = len(password) > 6
    digit_test1 = max([ch.isdigit() for ch in password])
    digit_test2 = not password.isdigit()
    return len_test & digit_test1 & digit_test2

June 18, 2021

Comments:

robertabegg on Aug. 29, 2021, 3:01 a.m.
I like the extra clarity over brevity :) Suggest digittest variables could be more explicit, e.g. digitatleast1, digitnot_all

Electronic Station

0 %

You ClassRoom Demo is Ready With the new tool CheckiO ClassRoom, you will be able to analyze your students' progress, have your own leaderboard, change missions order on the map, and so on.