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First solution in Speedy category for Acceptable Password III by alterGNU
# Taken from mission Acceptable Password II
def is_acceptable_password(password: str) -> bool:
if (len(password) > 6) :
t1, t2 = False, False
for i in password:
if i.isdigit() and not(t1):
t1 = True
if not(i.isdigit()) and not(t2):
t2 = True
if t1 and t2:
return True
return False
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567m') == True
assert is_acceptable_password('1234567') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
May 14, 2021
