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Simple Regex solution in Clear category for Acceptable Password III by WreakHavoc
import re
# This exact same solution works for both missions Acceptable Password II and III
def is_acceptable_password(password: str) -> bool:
return bool(match := re.match(r'^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{6,}$',password))
July 8, 2020
