def checkio(number):
if 0<number<=1000:
if number%15==0:
print("Fizz Buzz")
elif number%3==0:
print("Fizz")
elif number%5==0:
print("Buzz")
else:
return str(number)
else:
print("Need >0 and <=1000")
Created at: 2015/06/05 09:09; Updated at: 2015/06/08 17:35