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The requirements are not expected

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def countneighbours(grid, row, col): boxsize = len(grid[0]) if all(boxsize == len(elem) for elem in grid) and 3 <= len(grid) <= 10 and 0 <= row <= boxsize and 0 <= col <= boxsize: sum = 0 xmin = max(0, col - 1) xmax = min(boxsize - 1, col + 1) ymin = max(0, row - 1) ymax = min(box_size - 1, row + 1) print (xmin, xmax), (ymin, ymax) for x in range(xmin, xmax + 1): for y in range(ymin, ymax + 1): if x != col or y != row: print x,y,grid[y][x] sum += grid[y][x] return sum else: return -1

The minimum box size is 3 and maximum is 10. It must be a box meaning len(row) == len(col). So my solution does not get validated and I have to account for infinately large arrays and rectangles.

From: http://www.checkio.org/mission/count-neighbours/solve/

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Created: March 18, 2015, 9:49 p.m.
Updated: March 19, 2015, 5:31 a.m.
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BenjaminLush