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efficient code for longest common prefix
 check = list(zip(*arr))
 res = ''
 for i in check:
     if all(map(lambda x:x==i[0],i)):
        res += i[0]
     else:
         break
 return res
Created: June 12, 2025, 6:17 a.m.
Updated: June 12, 2025, 6:17 a.m.
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