Hi guys and hepl me please. I broke my head, phinking and trying another variants in my code. He work, but his output not check test for elements ".

Your result:["4","4","4","4","6","6","2","2"]
Right result:[4,4,4,4,6,6,2,2]
Fail:frequency_sort([4,6,2,2,6,4,4,4])

I try convert my output on list, string and dict, but whenewer - don't check.

    def frequency_sort(items):
        array = {}
        for i in items:
            if i in array:
                array[i] += 1
            else:
                array[i] = 1
        sorted_array = sorted(array.items(), key=lambda kv: kv[1], reverse=True)
        counter = 0
        new_text = []
        for i in sorted_array:
            new_text.extend(str(sorted_array[counter][0]) * (sorted_array[counter][1]))
            counter +=1
        return new_text

    if __name__ == '__main__':
        print("Example:")
        print(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4]))

        # These "asserts" are used for self-checking and not for an auto-testing
        assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
        assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
        assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
        assert list(frequency_sort([])) == []
        assert list(frequency_sort([1])) == [1]
        print("Coding complete? Click 'Check' to earn cool rewards!")